Increasing girth could be easier for bigger dicks than for skinnier ones.

[Doggedly_positive]

I've been thinking about the physics of cycling and VED sessions and have come to realise that the bigger your girth, the greater is the stretching (tangential or hoop) force on the tissues.

This is because the tangential force, F, on the tunica is directly proportional to the pressure ,P, of the internal fluid and to the diameter of the dick, D, according to the equation:

F = PD/2 per unit length.

This means that for the same inflated pressure, the stretching force on the tissues is 50% more for a 6" girth than for a 4" one.

That is a huge difference, and one that unfairly favours the guy who doesn't need the extra girth over the desperate guy who is never going to achieve the same stretching force.

As an aside, the axial force that would tend to lengthen this dick is much less than the tangential or hoop force, because it acts only on the much smaller cross-sectional area, which is πd^2/4, resulting in a "length-stretching" force only half that of the "girth-increasing" force.

So there you have it. Forget about making your dick longer by cycling or by using a VED.
You have a 100% greater chance of increasing your girth than your length.

Sorry.

[ElbowRoom]

Isn’t that force spread over a larger area? Distribution of force has to be as important as total force applied.

Oh, and you have too much time on your hands.

[cbinspok]

I enjoyed the math lesson:)
I know this, my youthful cock was a 7.25 pencil dick, I could pick locks with it Lol , got complaints in college from girls and had to learn how to wield my weapon.
at 47 " the big bedroom break happened " zero cock for over a year, Dr's and gross amounts of viagra and ten more years brought me to the implant. with a 6.5 ". but a bit fatter then.
post surgery, after a year 6.75. pretty happy wth this, Use the VED to enjoy the stretch feeling and it allows me to pull it to that 7, 7.25 mark that I still miss, plus you're correct i get a much fatter dick for several hours ( a band is used for some of that time ) yeah it's all temporary and my junk retreats to the stable 6.75" but its a nice visit to my youth with added girth .

[Doggedly_positive]

Isn’t that force spread over a larger area? Distribution of force has to be as important as total force applied.

Oh, and you have too much time on your hands.

Let's apply it to a hypothetical real world case.

Choosing round numbers for clarity and the metric system because I live in the real world, let's assume a 15cm length and a 3cm diameter pumped up to 1 kg/cm2.

Looking at the half cylinder (lengthwise rectangular cross-section), the total force perpendicular to the rectangular plane is the pressure times the area, which is
PxLxD = 1 X 15 X 3 = 45 kg.

But this force acts on both long sides of the rectangle, so each 15 cm side carries half that, or PxLxD/2 = 22.5 kg or 22.5/15 kg per cm, which reduces to 1.5 kg/cm.

It can therefore be seen that a member with a diameter of 4 cm would carry 60 kg total, or a stretching (tangential or hoop) force of 2 kg/cm, which is one third more than the first example.

[Doggedly_positive]

Looking at the axial (length stretching force) now, the total force is again pressure times area, which in this case is the circular cross-sectional area of the member in question. This gives us

F = P x πr^2 or

F = P x π(D/2)^2 or

F = P x π (D^2)/4

For the 4 cm diameter example used previously,

F = 1 X 4π or 12.6 kg.

This time, the stretching force is carried by the circumference of the circle, which is π x D or 12.6 cm long.

Combining these two equations produces the result that the axial force = 1 kg/cm, which is only half of the tangential force.

Sadly, it is still one third more than the 3 cm diameter example above, so again, the winner takes all.